费用流板子
还是一道板子题。。先练练手
#include#define INF 0x3f3f3f3f#define full(a, b) memset(a, b, sizeof a)using namespace std;typedef long long ll;inline int lowbit(int x){ return x & (-x); }inline int read(){ int X = 0, w = 0; char ch = 0; while(!isdigit(ch)) { w |= ch == '-'; ch = getchar(); } while(isdigit(ch)) X = (X << 3) + (X << 1) + (ch ^ 48), ch = getchar(); return w ? -X : X;}inline int gcd(int a, int b){ return a % b ? gcd(b, a % b) : b; }inline int lcm(int a, int b){ return a / gcd(a, b) * b; }template inline T max(T x, T y, T z){ return max(max(x, y), z); }template inline T min(T x, T y, T z){ return min(min(x, y), z); }template inline A fpow(A x, B p, C lyd){ A ans = 1; for(; p; p >>= 1, x = 1LL * x * x % lyd)if(p & 1)ans = 1LL * x * ans % lyd; return ans;}const int N = 5005;const int M = 50005;int n, m, s, t, head[N], cnt, inq[N], pre[N], incf[N], dist[N], ans, mf;struct Edge { int v, next, f, cost; } edge[M<<1];void addEdge(int a, int b, int f, int cost){ edge[cnt].v = b, edge[cnt].f = f, edge[cnt].cost = cost, edge[cnt].next = head[a], head[a] = cnt ++; edge[cnt].v = a, edge[cnt].f = 0, edge[cnt].cost = -cost, edge[cnt].next = head[b], head[b] = cnt ++;}bool spfa(){ full(dist, INF), full(inq, false); full(pre, 0), full(incf, INF); queue q; q.push(s); dist[s] = 0, inq[s] = true; while(!q.empty()){ int cur = q.front(); q.pop(); inq[cur] = false; for(int i = head[cur]; i != -1; i = edge[i].next){ int u = edge[i].v; if(edge[i].f > 0 && dist[u] > dist[cur] + edge[i].cost){ dist[u] = dist[cur] + edge[i].cost; pre[u] = i, incf[u] = min(incf[cur], edge[i].f); if(!inq[u]) q.push(u), inq[u] = true; } } } return dist[t] != INF;}void mcmf(){ while(spfa()){ int cur = t; while(cur != s){ int i = pre[cur]; edge[i].f -= incf[t], edge[i^1].f += incf[t]; cur = edge[i^1].v; } mf += incf[t]; ans += dist[t] * incf[t]; }}int main(){ full(head, -1), cnt = 2; n = read(), m = read(), s = read(), t = read(); for(int i = 0; i < m; i ++){ int u = read(), v = read(), w = read(), c = read(); addEdge(u, v, w, c); } mcmf(); printf("%d %d\n", mf, ans); return 0;}